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Effect pedal circuits: the Buffer | Effect Pedal Kits
https://effectpedalkits.com/blog/effect-pedal-circuits-the-buffer/#:~:text=Audio%20buffers%20provide%20a%20high%20input%20impedance%20for,require%20more%20current%20without%20degrading%20your%20audio%20signal.
What is an audio buffer? – PS Audio
https://www.psaudio.com/askpaulvideo/what-is-an-audio-buffer/
7 comments on “What is an audio buffer?” Richtea says: April 12, 2021 at 10:35 am. ... Paul describes an amplifier with unity voltage gain, high input impedance, low output impedance, and sufficient output current capability to drive a range of different loads. It creates an output voltage that is exactly the same as the input voltage.
High Impedance Audio Buffer With JFET | Full Project …
https://www.electronicsforu.com/electronics-projects/high-impedance-audio-buffer-jfet
The high impedance audio buffer circuit described here can be used to enhance the AC input impedance of audio amplifiers that are used with pickups in musical instruments. Some signal sources for preamplifiers, passive pickups for electric guitars or sensors based on capacitors require very high-impedance of over 5-mega-ohm.
Buffers, impedance and other internet lore – Mr. Black
https://www.mrblackpedals.com/blogs/straight-jive/6629774-buffers-impedance-and-other-internet-lore
A buffer, by definition, is an impedance transformation circuit. In the guitar world, they can be loosely defined as current amplifiers. They amplify signal strength (current), but ignore signal amplitude (voltage). This is where the terms "unity gain buffer" and "strong signal" come into play when buffers are marketed.
Impedance Matching & Buffers - Engineers Garage
https://www.engineersgarage.com/impedance-matching-buffers/
BUFFERS Imagine a device that has an input resistance much greater that the source resistance of the microphone say 50K ohm (Ra) and output resistance much less than input resistance of amplifier say 1 ohm (Rb). Also let the design of the device be such that input voltage is almost equal to output voltage that is Vout/Vin=1.
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