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High Pass Filter- Explained - Learning about Electronics
http://www.learningaboutelectronics.com/Articles/High-pass-filter.php#:~:text=To%20build%20a%20high%20pass%20filter%2C%20the%20components,frequency%20of%20an%20RC%20circuit%20is%2C%20frequency%3D%201%2F2%CF%80RC.
How to Build Audio Filter Circuits - Circuit Basics
https://www.circuitbasics.com/audio-filters/
High pass filter The gain is set with resistors R3 and R4 as in the previous circuit. With this filter, C1 is 1 uF and R1 is 8.2K Ohms, so the cutoff frequency is: Fc = 1 / (2 * Pi * 8.2k * 1 uF) Fc = 19.4Hz Remember to convert the resistance and capacitance values to Ohms and Farads before performing the calculation.
java - How to implement a high-pass filter for an audio ...
https://stackoverflow.com/questions/28252665/how-to-implement-a-high-pass-filter-for-an-audio-signal
Here is my high pass filter method: public void highPassFilter (double []frequency, int samplerate) { double [] f = new double [frequency.length]; for (int n=1; n<frequency.length; n++) { f [n] = (double)frequency [n]/samplerate; double x = (double)Math.exp (-2 * Math.PI * f [n]); double []a = new double [] { (1+x)/2, - (1+x)/2 }; double []b = new double [] { x }; } }
How to Design a High-Pass and Low Pass Filter Circuits ...
https://www.homemade-circuits.com/design-high-pass-filter-circuit-quickly/
As proposed, to design a high-pass filter circuit quickly, the following formulas and the subsequent steps can be used for calculating the relevant resistors and capacitors. First, select an appropriate value arbitrarily for C1 or C2, both can be identical. Next, calculate R1 by using the following formula: R1 = 1 / √2 x π x C1 x Frequency
High Pass Filter - Passive RC Filter Tutorial
https://www.electronics-tutorials.ws/filter/filter_3.html
The cut-off frequency, corner frequency or -3dB point of a high pass filter can be found using the standard formula of: ƒc = 1/ (2πRC). The phase angle of the resulting output signal at ƒc is +45o. Generally, the high pass filter is less distorting than its equivalent low pass filter due to the higher operating frequencies.
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