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Cambridge Audio Azur 840A | Full Specifications & Reviews
https://productz.com/en/cambridge-audio-azur-840a/p/VV1Px#:~:text=Connectivity%20%20%20Connectivity%20technology%20%20%20Wired,Audio%20%28L%2FR%29%20in%20%20%208%20Edit%20
Cambridge Audio 840A integrated amplifier - The …
https://www.theabsolutesound.com/articles/cambridge-audio-840a-integrated-amplifier
by Chris Martens. Nov 10th, 2008. A. A. A. The azur 840A is the most flexible, most powerful, and best-sounding integrated amplifier that the British firm Cambridge Audio has ever built, and it even introduces a new Class XD mode of amplifier operation (see the sidebar). What is more, it also serves as a “multizone” integrated amplifier, providing dual A-BUS interfaces that can …
Cambridge Audio Azur 840A | Full Specifications & Reviews
https://productz.com/en/cambridge-audio-azur-840a/p/VV1Px
Cambridge Audio Azur 840A | Full Specifications: Amplifier class: D, Purpose: Home, Frequency range: 10, 50000, Input impedance: 20000, Signal-to-Noise Ratio (SNR) : 93, Total Harmonic Distortion (THD) : 0.01, Peak power per channel: 200, RMS power output per channel (4 Ohm) : 200, RMS power output per channel (8 Ohm)
Cambridge Audio Azur 840A V2.0 review | What Hi-Fi?
https://www.whathifi.com/cambridge-audio/azur-840a-v20/review
Straight from the box, the Cambridge sounds bright and aggressive. After a day's warming, the sound calms to merely brash and, at the end of a second day, the 840A has gained equilibrium. A run through Goldfrapp's Supernature reveals this to equate to a detailed, open, dynamic and expansive sound. Voices are quite superbly poised and natural, low frequencies …
Two pairs of speakers on a Cambridge azur 840A amplifier a ...
https://www.avforums.com/threads/two-pairs-of-speakers-on-a-cambridge-azur-840a-amplifier-a-problem.1113117/
Though it is implied that the 840A is, if not stable, then at least tolerant of loads a low as 3 ohms, (two 6 ohms speakers). I would not recommend testing this, but it is not uncommon for better amps to be more tolerant of loads dropping below 4 ohms. The formula you want is - Rt = (R1 x R2) / (R1 + R2)
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